By all means, do have a go at solving it, before reading our solution below.
The first, slightly non-obvious step is to raise both sides of the equation to the power of 3:
\[ \left( x^{x^3} \right)^3 = \left( \frac{1}{2^{1/6}} \right)^3 \]
Rearranging that a bit, we have:
\[ x^{3x^3} = \frac{1}{2^{3/6}} \]
And so:
\[ \left( x^3 \right) ^{x^3} = \left( \frac{1}{2} \right) ^ {1/2} \hspace{10 mm} (Equation 2) \]
If
\[ a^a = b^b \]
then we have a solution:
\[a=b\]
So, returning to Equation 2, we have: \[x^3=1/2 \] And hence: \[x=\frac{1}{2^{1/3}} \] So, we have a solution to equation 1. But are there any others?
In fact, it is possible have \[ a \neq b \] when \[ a^a = b^b \] For example: \[ \left( \frac{1}{4} \right)^{1/4} = \left( \frac{1}{2} \right)^{1/2} \] So, returning to equation 2, we can see that another solution for x is when: \[ x^3 = \frac{1}{4} \] And hence: \[ x = \frac{1}{2^{2/3}} \] So, our solutions for x are: \[ \frac{1}{2^{1/3}} \hspace{4 mm} and \hspace{4 mm} \frac{1}{2^{2/3}} \] But are there other solutions?
If we let \[ z=x^3 \] then, returning to equation 2 we have: \[ z^z= \frac{1} {\sqrt{2}} \hspace{10 mm} \] We can plot \(z^z \) for positive z: We can see that \(z^z\) decreases in the range 0 to 1/e, after that it increases and keeps on increasing. So for positive z, we will have a maximum of two solutions to \( z^z = k\), where k is some constant. We have two solutions already, so we now know there aren't any more,
unless of course we want to investigate negative or complex solutions...
So, returning to Equation 2, we have: \[x^3=1/2 \] And hence: \[x=\frac{1}{2^{1/3}} \] So, we have a solution to equation 1. But are there any others?
In fact, it is possible have \[ a \neq b \] when \[ a^a = b^b \] For example: \[ \left( \frac{1}{4} \right)^{1/4} = \left( \frac{1}{2} \right)^{1/2} \] So, returning to equation 2, we can see that another solution for x is when: \[ x^3 = \frac{1}{4} \] And hence: \[ x = \frac{1}{2^{2/3}} \] So, our solutions for x are: \[ \frac{1}{2^{1/3}} \hspace{4 mm} and \hspace{4 mm} \frac{1}{2^{2/3}} \] But are there other solutions?
If we let \[ z=x^3 \] then, returning to equation 2 we have: \[ z^z= \frac{1} {\sqrt{2}} \hspace{10 mm} \] We can plot \(z^z \) for positive z: We can see that \(z^z\) decreases in the range 0 to 1/e, after that it increases and keeps on increasing. So for positive z, we will have a maximum of two solutions to \( z^z = k\), where k is some constant. We have two solutions already, so we now know there aren't any more,
unless of course we want to investigate negative or complex solutions...